Calendar Problems Practice Test 3 is an easy long practice set of 50 multiple-choice questions on calendar problems, created by ReadyGo Learn for candidates preparing for SSC CGL and other staff-selection and government recruitment exams. It is test 3 in the Calendar Problems series on TestMint. This is a paid test priced at ₹99; a small convenience fee applies at checkout.
What this test covers
- Calendar Problems: 50 questions
Test details
| Questions | 50 |
|---|---|
| Duration | 50 minutes |
| Marks | 1 per question, 50 in total |
| Negative marking | 0.25 mark for each wrong answer |
| Difficulty | Mostly easy |
| Access | ₹99 |
A sample question from this test
How many days are there from 6 August 1993 to 19 October 1994, counting the later date but not the earlier one?
- 444
- 438
- 446
- 439
Answer: D. 439. The difference between the two dates is 439 days (counting the later date but not the earlier one).
How to approach this test
Count odd days: 7 days make a week, so only the remainder after dividing the number of days by 7 shifts the weekday.
This set leans easy, so use it to confirm that you can solve the basic pattern accurately before you move to harder sets. At 50 questions in 50 minutes, you have about 60 seconds per question on average. After you submit, review every wrong or guessed answer using the explanations.
Keep practising
Continue with all SSC CGL mock tests, free mock tests, a guide to preparing this topic and how to review your mistakes.